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##若何常州手游开发获取Android建筑唯一ID？
###问题 每一个android建筑都有唯一ID吗？要是有？怎么用java非常简略获得呢？
###回答1（非常佳）
若何获得android唯一码？
好处：
1.不需求特定权限.
2.在99.5% Android装配（包含root过的）上，即API => 9，包管唯一性.
3.重装app以后仍能获得相像唯一值.
伪代码：
if API => 9/10: (99.5% of devices)
return unique ID containing serial id (rooted devices may be different)
else
return unique ID of build information (may overlap data - API < 9)
代码:
/**
* Return pseudo unique ID
* @return ID
*/public static String getUniquePsuedoID() {
// If all else fails, if the user does have lower than API 9 (lower
// than Gingerbread), has reset their device or 'Secure.ANDROID_ID'
// returns 'null', then simply the ID returned will be solely based
// off their Android device information. This is where the collisions
// can happen.
// Thanks http://www.pocketmagic.net/?p=1662!
// Try not to use DISPLAY, HOST or ID - these items could change.
// If there are collisions, there will be overlapping data
String m_szDevIDShort = "35" + (Build.BOARD.length() % 10) + (Build.BRAND.length() % 10) + (Build.CPU_ABI.length() % 10) + (Build.DEVICE.length() % 10) + (Build.MANUFACTURER.length() % 10) + (Build.MODEL.length() % 10) + (Build.PRODUCT.length() % 10);
// Thanks to @Roman SL!
// http://stackoverflow.com/a/4789483/950427
// Only devices with API >= 9 have android.os.Build.SERIAL
// http://developer.android.com/reference/android/os/Build.html#SERIAL
// If a user upgrades software or roots their device, there will be a duplicate entry
String serial = null;
try {
serial = android.os.Build.class.getField("SERIAL").get(null).toString();
// Go ahead and return the serial for api => 9
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
} catch (Exception exception) {
// String needs to be initialized
serial = "serial"; // some value
}
// Thanks @Joe!
// http://stackoverflow.com/a/2853253/950427
// Finally, combine the values we have found by using the UUID class to create a unique identifier
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();}
###常州游戏开发培训回答2 好处：
1.不需求特定权限.
2.在100% Android装配（包含root过的）上，包管唯一性.
缺点
1.重装app以后不行获得相像唯一值.
private static String uniqueID = null;
private static final String PREF_UNIQUE_ID = "PREF_UNIQUE_ID";
public synchronized static String id(Context context) {
if (uniqueID == null) {
SharedPreferences sharedPrefs = context.getSharedPreferences(
PREF_UNIQUE_ID, Context.MODE_PRIVATE);
uniqueID = sharedPrefs.getString(PREF_UNIQUE_ID, null);
if (uniqueID == null) {
uniqueID = UUID.randomUUID().toString();
Editor editor = sharedPrefs.edit();
editor.putString(PREF_UNIQUE_ID, uniqueID);
editor.co毫米it();
}
}
return uniqueID;
}
###回答3（需求有电话卡）
好处： 1.重装app以后仍能获得手机App外包相像唯一值.
代码：
final TelephonyManager tm = (TelephonyManager) getBaseContext().getSystemService(Context.TELEPHONY_SERVICE);
final String tmDevice, tmSerial, androidId;
tmDevice = "" + tm.getDeviceId();
tmSerial = "" + tm.getSimSerialNumber();
androidId = "" + android.provider.Settings.Secure.getString(getContentResolver(), android.provider.Settings.Secure.ANDROID_ID);
UUID deviceUuid = new UUID(androidId.hashCode(), ((long)tmDevice.hashCode() << 32) | tmSerial.hashCode());
String deviceId = deviceUuid.toString();
服膺：要获得如下权限
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
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